bci2000.org BBS

Hello all~

I have a question about 1-D cursor task speed.
below is our cursor task result.
I don't know how to calculate the bits transferred.
Total time is 118 sec for this run

Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred.
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RHY_taskS001.applog
Thu Jul 29 15:19:41 2010

Thank you

Young Hak Shin

Check out the bit rate definition in the Wolpaw et al., 2002, review article in Clinical Neurophysiology.

Gerv

Thank you for your response,

I have checked the bit rate (bits/trial) equation
B=logN + PlogP + (1-P)log[(1-P)/N-1)].
so, below our result case

Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred

P = 1 , B = 1
And 17.8394 means 17.8394 bits/min(trials/min) ?
or 17.8394 bits/118sec ?

It means that 17.8 bits have been transferred in total. To obtain a bitrate in bits/sec, divide by the duration, i.e. by 118sec.