Hello all~
I have a question about 1D cursor task speed.
below is our cursor task result.
I don't know how to calculate the bits transferred.
Total time is 118 sec for this run
Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred.
=====================
RHY_taskS001.applog
Thu Jul 29 15:19:41 2010
Thank you
Young Hak Shin
cursor task speed

 Posts: 10
 Joined: 06 Jul 2010, 09:00
Thank you for your response,
I have checked the bit rate (bits/trial) equation
B=logN + PlogP + (1P)log[(1P)/N1)].
so, below our result case
Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred
P = 1 , B = 1
And 17.8394 means 17.8394 bits/min(trials/min) ?
or 17.8394 bits/118sec ?
I have checked the bit rate (bits/trial) equation
B=logN + PlogP + (1P)log[(1P)/N1)].
so, below our result case
Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred
P = 1 , B = 1
And 17.8394 means 17.8394 bits/min(trials/min) ?
or 17.8394 bits/118sec ?
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