cursor task speed

Known Issues and Problems with BCI2000
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Shin Young Hak
Posts: 10
Joined: 06 Jul 2010, 09:00

cursor task speed

Post by Shin Young Hak » 30 Jul 2010, 09:38

Hello all~

I have a question about 1-D cursor task speed.
below is our cursor task result.
I don't know how to calculate the bits transferred.
Total time is 118 sec for this run

Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred.
=====================
RHY_taskS001.applog
Thu Jul 29 15:19:41 2010

Thank you

Young Hak Shin

gschalk
Posts: 615
Joined: 28 Jan 2003, 12:37

bit rate

Post by gschalk » 30 Jul 2010, 15:08

Check out the bit rate definition in the Wolpaw et al., 2002, review article in Clinical Neurophysiology.

Gerv

Shin Young Hak
Posts: 10
Joined: 06 Jul 2010, 09:00

Post by Shin Young Hak » 02 Aug 2010, 08:21

Thank you for your response,

I have checked the bit rate (bits/trial) equation
B=logN + PlogP + (1-P)log[(1-P)/N-1)].
so, below our result case

Run #2 started
Run 2 finished: 20 trials, 18 hits, 2 invalid.
100% correct, 17.8394 bits transferred

P = 1 , B = 1
And 17.8394 means 17.8394 bits/min(trials/min) ?
or 17.8394 bits/118sec ?

mellinger
Posts: 1071
Joined: 12 Feb 2003, 11:06

Post by mellinger » 03 Aug 2010, 10:56

It means that 17.8 bits have been transferred in total. To obtain a bitrate in bits/sec, divide by the duration, i.e. by 118sec.

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